' 劉任昌集合{},字典{key:value,},元組(),清單或陣列[]'
p = ("台積電", "鴻海", "聯發科")
r = {"台積電", "鴻海", "聯發科"}
s = ["台積電", "鴻海", "聯發科"]
t = ["中華電", "台塑化", "台達電"]
d= {2330:"台積電",2317:"鴻海",2454:"聯發科"}
u = s
v = s.copy()
s.extend(t) #原來的 s=s.extend(t)是錯誤
i = 0
for a in r: #然後嘗試取代p為s(產生六個),r(產生三個)
i = i+1
print("台灣第" + str(i) + "大的公司是")
print(" " + a)
影片239
w3schools期中考截圖
微軟VS Code編輯tkinter圖形使用者介面
影片240
VS Code截圖
VS Code程式碼
#劉任昌改顏色blue, purple, 元組t 增加,32
from tkinter import * #從函式庫 tkinter 輸入所有 * 方法
from math import * #從函式庫 math 輸入所有 * 方法
t = (3,4,5,6,7,8,9,10,11,12,16,20,32) #宣告一元組tuple(...)
tk = Tk()
tk.title("劉任昌視窗使用者介面GUI")
canvas = Canvas(tk, width=500, height=500)
canvas.pack()
def show(event): #定義由事件event(按鈕選單)呼叫的函數show
cx, cy, cr = 210, 210, 200 #宣告圓中心座標cx, cy半徑cr
x, y =[],[] #宣告二陣列[...]
k = s.get() #取得 ge t按鈕選單的選擇變數
u = 2 * pi / k #使用模組 math 圓周率 pi
for i in range(k):
x.append(cx + cr*cos(i*u)) #加入陣列的元素
y.append(cy + cr*sin(i*u)) #使用模組 math 三角函數cos, sin
for i in range(k-1):
canvas.create_line(x[i], y[i], x[i+1], y[i+1])
canvas.create_line(x[k-1], y[k-1], x[0], y[0]) #可考慮增加width寬度,fill顏色
def diagonal():
cx, cy, cr = 210, 210, 200 #宣告圓中心座標cx, cy半徑cr外來學繼承 inheritance
x, y =[],[] #宣告二陣列[...]
k = s.get() #取得 ge t按鈕選單的選擇變數
u = 2 * pi / k #模組 math 圓周率 pi
for i in range(k):
x.append(cx + cr*cos(i*u)) #加入陣列的元素
y.append(cy + cr*sin(i*u))
for i in range(k):
for j in range(i+2, k):
canvas.create_line(x[i], y[i], x[j], y[j], fill="red", width=3)
s = IntVar(tk)
combo = OptionMenu(tk, s, *t, command = show).pack() #下拉式按鈕combobox
button = Button(tk, text="對角線", command = diagonal).pack()#按鈕button
tk.mainloop()
w3schools練習截圖 w3schools程式碼 #劉任昌集合set{},元組tuple(), 串列或清單list[], #字典dict{key:value,鍵:值} d = {2330:"台積電",2317:"鴻海",2454:"聯發科",6505:"台塑化"} s = {"台積電", "鴻海", "聯發科","台塑化"} t = ("台積電", "鴻海", "聯發科","台塑化") list = ["台積電", "鴻海", "聯發科","台塑化"] print(type(d),type(s),type(d),type(list)) print("台灣市場價值最大三家公司集合set列出") print(s) #練習迴圈 for a in s: print(a) print("聯發科位置:" + str(t.index("聯發科"))) """整個區塊註解前後加上連續三個引號, str將數字轉成字串 才能 和其他字串相接the set list is unordered, meaning: the items will appear in a random order. # Refresh this page to see the change in the result. """ w3schools集合方法 Python has a set of built-in methods that you can use on sets. Method Description add() Adds an element to the set clear() Removes all the elements from the set copy() Returns a copy of the set differenc...
https://www.blogger.com/blog/post/edit/preview/4399220548584548192/404587685510023700
回覆刪除https://xdrcfvghyujiok8945656.blogspot.com/2023/04/vs-codepythongui.html
回覆刪除https://jasperyang.blogspot.com/2023/04/vs-codepythongui.html
回覆刪除作者已經移除這則留言。
回覆刪除https://hhhaann.blogspot.com/2023/04/vs-codepythongui.html
回覆刪除https://cpc920508123.blogspot.com/2023/04/vs-codepython.html
回覆刪除https://pandora-mo.blogspot.com/2023/04/vs-codepython.html
回覆刪除https://trequiem.blogspot.com/2023/04/vs-code-pythongui.html
回覆刪除https://jdoifjopq1264.blogspot.com/2023/04/vs-codepythongui.html
回覆刪除https://enchenghu0905.blogspot.com/2023/04/vs-codepythoncui.html
回覆刪除https://chenyouzheng0329.blogspot.com/2023/04/vs-codepythongui.html
回覆刪除https://spencer0309.blogspot.com/2023/04/vs-code-pythongui.html
回覆刪除https://wutimothy.blogspot.com/2023/04/vs-codepythongui.html
回覆刪除https://d11150108.blogspot.com/2023/04/vs-codepythongui.html
回覆刪除https://d11150112.blogspot.com/2023/04/vs-codepythongui.html
回覆刪除https://zongde824.blogspot.com/2023/04/vs-codepythongui.html
回覆刪除https://cindy-javascript.blogspot.com/2023/04/vs-codepython.html
回覆刪除https://643gjeytfru4312.blogspot.com/2023/04/vs-codepythongui.html
回覆刪除https://jjjjjyyy.blogspot.com/2023/04/vs-codepythongui.html
回覆刪除https://www.blogger.com/blog/post/preview/8530990375848508323/839623689280227101
回覆刪除https://iuytjhg5261.blogspot.com/2023/04/vs-codepythongui.html
回覆刪除https://html-css-javascript-yaoto.blogspot.com/2023/04/vs-codepythongui.html
回覆刪除https://d11150116.blogspot.com/2023/04/vs-codepythongui.html
回覆刪除https://enchenghu0905.blogspot.com/2023/04/vs-codepythongu.html
回覆刪除